Relations for plane-parallel plates derived from Snell's law
Various equations can be derived from the law of refraction of light at material interfaces (Snell's law). Here we introduce some practical ones.
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Image position of convergent light incident perpendicularly on a plane-parallel plate
The position of the real image relative to the virtual image is determined for two cases: when the real image is inside the plane-parallel plate, and when it is beyond the plane-parallel plate.

(1) When the real image is in a plane-parallel plate:

*For dimensional notation, see Appendix: Direction and sign of one-dimensional vectors and angles
Here, dh, dθ1, and dθ2 are assumed to be minute quantities.
The conditions shown in the figure can be expressed as the following equations:

Here, the second equation is Snell's law. Also, since dθ1 and dθ2 are infinitesimal quantities, the following can be said:

So the original equation can be replaced with:

Solving this leads to the following:

(2) When the real image is beyond the plane-parallel plate:

*For dimensional notation, see Appendix: Direction and sign of one-dimensional vectors and angles
Here, dh, dθ1, and dθ2 are assumed to be minute quantities.
The conditions shown in the figure can be expressed as the following equations:

Here, the second equation is Snell's law. Also, since dθ1 and dθ2 are infinitesimal quantities, the following can be said:

So the original equation can be replaced with:

Solving this leads to the following:

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Image position when a parallel plate is placed at an angle to the optical axis
Consider the following light beam that is obliquely incident on a parallel plane plate and forms an image at the exit point. Calculate Δx and Δy in this case.

Here, dh, dθ1 , and dθ2 are small quantities.
The conditions shown in the figure can be expressed as follows:

Here, we will explain the formula for ④. Because dθ1 and dθ2 are minute, if we consider the red line and the green dotted line to be parallel, the width of the light beam before it enters the boundary surface will be cosθ1 /cosθ2 times the width of the light beam after it passes through the boundary surface, as shown below. Taking this into consideration, we have formulated ④.

Differentiate both sides of ③ to get

From ①, ②, ③', ④, and ⑤, eliminating s, xA, xB, x0, dh, dθ1, and dθ2, we get

Here, from ① and ⑥,

Also, from ③,

Therefore, the solution we seek can be expressed as follows:

Furthermore, by applying ③ and eliminating θ2, we get


As a specific example, if θ1 =45[deg] and n=1.5, the result will be as follows.

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Image position when a parallel plate is placed at an angle to the optical axis
Consider the following optical arrangement:

dθ1 and dθ2 are assumed to be minute amounts, and the longitudinal spherical aberration δs and the horizontal spherical aberration δx are calculated.
The conditions shown in the figure can be expressed as the following equations:

① and ③ represent Snell's law, and ⑤ represents the numerical aperture.
From ①, ②, and ⑤,

From ③ and ④,

From ②' and ④', the longitudinal spherical aberration is as follows:

From ⑥ and ⑦, the lateral spherical aberration is as follows:

The amount of spherical aberration is shown in the diagram below: As can be seen from the diagram, for the same plate thickness, the amount of spherical aberration peaks when the relative refractive index is around 1.6.


Here, the influence of aberration will be considered.
The point image resolution (Airy disk radius) due to wave optics diffraction broadening is expressed by the following formula:

As a rough guideline, when δx is much smaller than δd , δd dominates the resolution, so the effect of δx is small. On the other hand, when δx is much larger than δd , δx dominates the resolution.
A graph comparing δx and δd is shown below. While this is only a rough guideline, at a wavelength of 532 nm, the effects of spherical aberration become dominant over the point image resolution due to diffraction spread when using cover glass (approximately 0.15 mm thick) with an NA of 0.32 or higher, and when using glass with a thickness of 1.5 mm with an NA of 0.18 or higher. At a wavelength of 1064 nm, the effects of spherical aberration become dominant over the point image resolution due to diffraction spread when using cover glass (approximately 0.15 mm thick) with an NA of 0.38 or higher, and when using glass with a thickness of 1.5 mm with an NA of 0.22 or higher.
